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Cannot Be Cast To Java.lang.comparable Treeset


ClassCastException is result of bad design and bad coding. Why there are no approximation algorithms for SAT and other decision problems? Why does the size of this std::string change, when characters are changed? With my stack that is Object, but in Krep's case using "new Comparable[...]" is probably better. his comment is here

Naturally, this code doesn't make sense; you would be putting a Long into your heap of Elements, and that's just not right. Comparator vs. Simple as that. The object's actual runtime class is Object[], which is not a subtype of E[] for whatever E is (unless E is Object). http://stackoverflow.com/questions/2112343/java-integer-obj-cant-cast-to-comparable

Cannot Be Cast To Java.lang.comparable Treeset

At runtime, you simply have public class Stack { Object[] array; int index; public Stack(int size) { array = new Object[size]; index = 0; } public void push(Object element) { array[index++] How to add, subtract days, months, years, hours fr... b) My telling you "the bag contains peanut M&Ms" is casting the bag's contents c) The broken teeth is what happens if the cast is wrong!! Map Keys need to be comparable to ensure a sort order in the map.

Black magic java generics ant pkg won't work for installing I2P Comparable - must override compareTo()??? So how are you "exposing" elements? Comparator in Java Sort LinkedList of User-Defined Objects in Java Category >> Collections If you want someone to read your code, please put the code inside

tags. Java Comparable With my stack that is Object, but in Krep's case using "new Comparable[...]" is probably better.

In this Java tutorial we will see Why java.lang.ClassCastException comes and how to resolve ClassCastException in Java. Ljava Lang Object Cannot Be Cast To Ljava Lang Comparable ThreadLocal in Java. Solution for implementing Comparable for a TreeSet The following is the code corrected (which implements Comparable): import java.util.TreeSet; class Dog implements Comparable { int size; Dog(int s) { http://stackoverflow.com/questions/27591061/ljava-lang-object-cannot-be-cast-to-ljava-lang-integer The code will work fine if, and only if, the cast is correct -- i.e., if the array really does contain objects that implement Comparable.

How to use? Compareto Java Actually in Java, you don't even get that far. java.lang.ClassNotFoundException: oracle.jdbc.driv... Powered by Blogger.

Ljava Lang Object Cannot Be Cast To Ljava Lang Comparable

In Doctor Strange what was the title of the book Stan Lee was reading in his cameo? Actually you can (it's a warning after all, not an error), but only if the rest of the code ensures that every interaction with the array respects the T type. Cannot Be Cast To Java.lang.comparable Treeset public class MyVertex implements Comparable { @Override public int compareTo(Object o) { // comparison logic goes here } } or alternately, you can pass a comparator to the constructor of TreeMap. Create Generic Array Java YA novel involving immortality via drowning more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology

James Brooks Gunslinger Ranch Hand Posts: 165 posted 7 years ago Hi ladies/gents, It's been a while and I'm looking at returning to grad school next semester, so I've dug out this content Rob Spoor Sheriff Posts: 20718 68 I like... How much time would it take for a planet scale Miller-Urey experiment to generate intelligent life How to decline a postdoc interview if there is some possible future collaboration? share|improve this answer answered Dec 23 '14 at 2:16 newacct 73.1k16107157 add a comment| up vote 1 down vote It's clear now. Treeset Comparator

How to create thread safe Singleton in Java - Java... So the cast is, theoretically, incorrect. TreeSet vs. http://homeshareware.com/cannot-be/operator-cannot-be-applied-to-java-lang-string.html It is saying that the method sort is not applicable and that it cannot be cast.

Unlike C-style languages, arrays are objects in Java. Java Queue If you want to sort using different order then you need to provide your own comparator. Still, we need some surrounding code. –Rohit Jain Aug 17 '13 at 18:59 I am trying to create an array of Element.

Why does the size of this std::string change, when characters are changed? "Carrie has arrived at the airport for two hours." - Is this sentence grammatically correct?

Comparable Check out the comparision and figure out when to use which. January 21, 2013 at 9:18 PM Farooq said... public class IntDriver { public static void main(String[] args) { Scanner keyboard = new Scanner(System.in); //Creating variables int data; boolean check = false; int choice; int size = 5; int increment Recursion in Java with example - Programming Techn...

What I meant was this: Stack stack = new Stack(10); stack.push("Hello World"); T[] array = stack.array; // called from inside class Stack itself ;) Object[] objects = array; // allowed since Why is Professor Lewin correct regarding dimensional analysis, and I'm not? Maybe it's nitpicking, but I don't agree with the underlined reasoning: you cannot "add anything", as the cast will fail. http://homeshareware.com/cannot-be/dependencies-cannot-be-applied-to-groovy-lang-closure-java.html super T>> { T[] array; public Stack(int size) { array = (T[])new Comparable[size]; } public T[] toArray() { T[] destination = (T[])new Comparable[array.length]; System.arraycopy(array, 0, destination, 0, array.length); return destination; }

Because you are storing in tree map which is a sorted map (sorted by keys). Next, one of two things happens: 1) You bite into a delicious handful of peanut M&Ms. 2) You break all your teeth because the bag is actually full of marbles. How to Count Occurrences of a Character in String ... java.lang.classcastexception java.util.arraylist cannot be cast to java.util.mapjava.lang.classcastexception ljava.lang.object cannot be cast to ljava.lang.comparablejava.lang.classcastexception ljava.lang.object cannot be cast to ljava.lang.integerjava.lang.classcastexception ljava.lang.object cannot be cast to java.util.listjava.util.arraylist cannot be cast to java.lang.comparable

You need to change that to: Object[] a = new Object[] {Integer.valueOf(1);}; java.util.Comparable x = (java.util.Comparable) a[0]; Even better, you should rename your Comparator class to something that doesn't collide with Istvan Kovacs Ranch Hand Posts: 100 posted 6 years ago Krep Lock wrote: public class MyArrayList extends MyListADT { T[] list = (T[]) new Object[maxSize]; } Exception in thread Join them; it only takes a minute: Sign up java.lang.ClassCastException: [Ljava.lang.Comparable; cannot be cast to up vote 3 down vote favorite I got the following exception in my code: Exception in public class Dog extends Animal // a Dog IS A Animal, but no dog can be compared :wink: public class Student extends Person implements Comparable // a Student IS A Person

I couldn't tell you for sure with you code though as it's incomplete. extends T> coll) For a thorough explanation, I recommend Java Generics and Collections by Maurice Naftalin Maurice and Philip Wadler. If so, how can you then successfully compare this object that was cast to Comparable if the method compareTo() is not implemented (interfaces are classes with no implemented methods, correct?)? We have a great list of items on our menu.\n Would you like to see these items sorted by name or by price?\n 1 for name, 2 for price, 3 to

The declaration should be public class MyArrayList

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