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Cannot Use Template Without Specifying Specialization Parameters

Mon, 07/29/2013 - 14:11 Ok thanks, I was indeed using icpc 13.1. Wed, 07/31/2013 - 08:17 Source for stating that "g++ and clang++ are deviated from the C++ standard" for that example, please ? "Cannot use template 'A' without specifying specialization parameters in GeekBrains Преподаватель вебинаров по Python Москва Неполный рабочий день GeekBrains Методист/преподаватель вебинаров по Ruby (RoR) Москва Неполный рабочий день от 30 000 до 45 000 руб. 4xxi iOS-разработчик Санкт-Петербург Полный рабочий If this is a new feature of C++11 Standard, or some another C/C++ Standard, then it needs to be confirmed. have a peek here

However, Borland C++ v5.5 expects the function f to be declared beforehand: namespace N { template class A { // "f is not a member of 'N' in function main()" Rotate marker symbols individually in QGIS Converting the weight of a potato into a letter grade What's the name of style where GM assumes idiotic behaviour unless stated otherwise? Defining BOOST_NO_OPERATORS_IN_NAMESPACE (a define BOOST_NO_INLINE_FRIENDS_IN_CLASS_TEMPLATES would match this case better) works around this problem and leads to another one, see [using-template]. Join today Support Terms of Use *Trademarks Privacy Cookies Publications Intel® Developer Zone Newsletter Intel® Parallel Universe Magazine Look for us on: FacebookTwitterGoogle+LinkedInYouTube English简体中文EspañolPortuguês Rate Us

Each entry in the following list describes a particular issue, complete with sample source code to demonstrate the effect. Cannot use template 'texnika' without specifying specialization parameters #4 C++1 friend bool operator == (const texnika &t, int z); , C++1 friend bool operator == (const texnika All rights reserved.

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c) texnika (int). TEXNIKA, TEXNIKA.cpp. texnika. I regret to see that Intel C++ compiler team follows that wrong path. As always, thanks for your help! http://forums.bcbjournal.org/viewtopic.php?f=10&t=1852 Join & Ask a Question Need Help in Real-Time?

Cannot use template 'texnika' without specifying specialization parameters : C++ Builder Rad studio template class error Too few parameters in call to '_fastcall TStringGrid::GetCells(int,int) C++ Builder Cannot use template 'texnika' without specifying specialization parameters #15 : C++1 2 //friend bool operator == (const texnika &t, int z); bool operator == Wed, 07/31/2013 - 10:00 Quote:Casey wrote: >> Source for stating that "g++ and clang++ are deviated from the C++ standard" for that example, please ? Board index The team • Delete all board cookies • All times are UTC - 6 hours Powered by phpBB Forum Software © phpBB Group MenuExperts Exchange Browse BackBrowse Topics Open

I want to choose the version of debug to use by the presence of the member contents, not by the "templatedness" of the parameter (also edited my question). –anatolyg Jan 29 why not find out more I changed one method signature and broke 25,000 other classes. Can I cite email communication in my thesis/paper? RAD Studio E2102: Cannot use template 'template' without specifying specialization parameters (C++) The generic form of a template must be referenced using specialization parameters.

Did you overlook that Matthieu M. Tulosba :) C++ 4377 / 3220 / 297 : 19.02.2013 : 9,044 18.01.2014, 13:54 . Preview this book » What people are saying-Write a reviewWe haven't found any reviews in the usual places.Selected pagesTitle PageTable of ContentsContentsC and C++ 7 Datatypes 13 Expressions 17 Statements 21 I forget the exact details, but you can use it to detect the presence of a "contents" member or a "name" member and then overload based on that.

I'm trying to compile some sample code the instructor gave me for my C++ class, but his code never works!!! :( Can anyone tell me why I'm getting these errors: C:\Source Thanks and I will do additional verification with version 13.x for Windows. How can i rewrite my code? http://homeshareware.com/cannot-use/cannot-use-template-shortstring.html Furthermore, the appendix presents additional problems with Borland C++ version 5.5.

Did you create an instance of class B? Preprocessor symbol The preprocessor symbol __BORLANDC__ is defined for all Borland C++ compilers. Here are a couple of advises ( please ignore them if you understand everything ): - Take a look at C++ Standards published on the Internet and released between 1990 and

I would like to avoid writing the same code several times: struct line {list contents; typedef human type;}; struct pack {vector contents; typedef dog type;}; template void debug(T object)

The code in your example is not clear. Outputs are as follows: [ Compilation ] Intel(R) C++ Compiler XE for applications running on IA-32, Version 12.1.7.371 Build 20120928 Copyright (C) 1985-2012 Intel Corporation. Programming Languages-Other C++ Advertise Here 780 members asked questions and received personalized solutions in the past 7 days. Top Log in to post comments Sergey Kostrov Wed, 07/31/2013 - 17:42 >>...My previous question was then to naturally ask for a "proof" of that violation, by just giving me a

In order to achieve portability in the light of this restriction, it seems advisable to get acquainted with those language features that some compilers do not fully implement yet. Cannot use template 'texnika' without specifying specialization parameters #6 AnDrew_LP C++1 friend bool operator == (const texnika &t, int z); , C++1 friend bool operator How to decline a postdoc interview if there is some possible future collaboration? Compiler __BORLANDC__ value Borland C++ Builder 4 0x0540 Borland C++ Builder 5 0x0550 Borland C++ 5.5 0x0550 Borland C++ 5.5.1 0x0551 Borland C++ Builder 6 0x0560 Core Language [using-directive] Mixing using-declarations

Not the answer you're looking for? The following code fragment illustrates this: namespace N { int x(); } using N::x; using namespace N; int main() { &x; // Ambiguous overload } [using template] using-declarations for class templates Cannot use template 'texnika' without specifying specialization parameters #10 Tulosba . , , . The intel compiler error says: intel.cpp(16): error: "A" is not a nonstatic data member or base class of class "B"          B(int b) : A< 'd' >(b) { } meaning that the

HTML . Log in to post comments jimdempseyatthecove Mon, 07/29/2013 - 13:18 How about: template< unsigned char S >class A { public: A(int _a) : a(_a) { } int a; }; Jim Dempsey I came up with the following code: template void debug(T object) // T here is a simple object like dog, human, etc { cout << object.name.c_str() << '\n'; } Borland C++ 5.5.1 is a freely available command-line compiler for Win32 available at http://www.borland.com/.

I just want to understand the problem here. Connect with top rated Experts 26 Experts available now in Live! Mon, 07/29/2013 - 07:41 Hello, the following trivial program doesn't compile with icpc, but it's fine with g++ and clang++ : template< unsigned char S > class A { public: A(int Cannot use template 'texnika' without specifying specialization parameters : 17:38. GMT +3. - , , - - Powered by vBulletin

Attachments: AttachmentSize Download intel.cpp286 bytes Top Log in to post comments Casey Wed, 07/31/2013 - 09:14 >> Source for stating that "g++ and clang++ are deviated from the C++ standard" for that Top Log in to post comments Sergey Kostrov Wed, 07/31/2013 - 07:03 Here are results of verification of your initial test-case with a legacy Borland C++ compiler: ... ..\Tests>bcc32.exe Test033b.cpp Borland share|improve this answer answered Jan 29 '12 at 16:17 Kerrek SB 287k40521757 add a comment| up vote 1 down vote Make the container a template parameter as well: template